Neural Network : Firing Rule

TABLE SHOWN BELOW DISPLAY THE    INPUT DATA   AND CORESSPONDING OUT DATA
APPLY THE FIRING RULE TO ABTAIN THE CORRECT TABLE USING. WE HAVE THE (0 TOUGHT SET) AND (1-TOUGHT SET)

X1:       0      0        0        0       1      1      1      1
X2:       0      0        1        1       0      0      1      1
X3:       0      1        0        1       0      1      0      1
OUT:      0      0       0/1      0/1     0/1     1     0/1     1

#include<stdio.h>
void print(int*arr,int n)
{
    int i;
    for(i=0;i<n;i++)
        printf("%d ",arr[i]);
    printf("\n\n");
}
int main()
{
    int i,j,counter,maxMatch,oneCount,zeroCount,current_j;
    int x1[]={0,0,0,0,1,1,1,1};
    int x2[]={0,0,1,1,0,0,1,1};
    int x3[]={0,1,0,1,0,1,0,1};

    int out[]={0,0,-1,-1,-1,1,-1,1};
    int newOut[8];

    for(i=0;i<8;i++)
        newOut[i]=out[i];
    for(i=0;i<8;i++)
    {
        counter=0;
        maxMatch=0;
        if(out[i]==-1)
        {
            for(j=0;j<8;j++)
            {
                counter=0;
                if(out[j]!=-1 && j!=i)
                {
                    if(x1[j]==x1[i])
                        counter++;
                    if(x2[j]==x2[i])
                        counter++;
                    if(x3[j]==x3[i])
                        counter++;
                }
                if(counter>maxMatch)
                    maxMatch=counter;
            }
            zeroCount=0;
            oneCount=0;
            for(j=0;j<8;j++)
            {
                counter=0;
                if(out[j]!=-1 && j!=i)
                {
                    if(x1[j]==x1[i])
                        counter++;
                    if(x2[j]==x2[i])
                        counter++;
                    if(x3[j]==x3[i])
                        counter++;

                    if(counter==maxMatch)
                    {
                        if(out[j]==0)
                            zeroCount++;
                        else if(out[j]==1)
                            oneCount++;
                    }
                }
            }
            if(zeroCount>oneCount)
                newOut[i]=0;
            else if(zeroCount<oneCount)
                newOut[i]=1;
            else
                newOut[i]=-1;
        }
    }
    printf("x1 : \n");
    print(x1,8);

    printf("x2 : \n");
    print(x2,8);

    printf("x3 : \n");
    print(x3,8);

    printf("old out : \n");
    print(out,8);

    printf("new out : \n");
    print(newOut,8);

    return 0;
}